Click the button below to see similar posts for other categories

Can You Illustrate the Relationship Between Polar and Cartesian Coordinates with Examples?

Polar coordinates and Cartesian coordinates are two different ways to show points on a flat surface. Each method has its own benefits.

Polar Coordinates:

  • They are written as (r,θ)(r, \theta), where:
    • rr is how far the point is from the center (the origin).
    • θ\theta is the angle measured from the right side (the positive x-axis).

Example:

Let’s change the polar point (5,π3)(5, \frac{\pi}{3}) into Cartesian coordinates:

  • We can use these formulas:
    • x=rcos(θ)x = r \cos(\theta)
    • y=rsin(θ)y = r \sin(\theta)

Calculating:

  • For xx:
    x=5cos(π3)=512=2.5x = 5 \cos\left(\frac{\pi}{3}\right) = 5 \cdot \frac{1}{2} = 2.5

  • For yy:
    y=5sin(π3)=5324.33y = 5 \sin\left(\frac{\pi}{3}\right) = 5 \cdot \frac{\sqrt{3}}{2} \approx 4.33

So, the polar point (5,π3)(5, \frac{\pi}{3}) is about (2.5,4.33)(2.5, 4.33) in Cartesian coordinates.

Cartesian Coordinates:

  • They are shown as (x,y)(x, y), where:
    • xx tells us how far to go left or right.
    • yy tells us how far to go up or down.

Example:

Let’s convert the Cartesian point (3,33)(3, 3\sqrt{3}) into polar coordinates:

  • We can use these formulas:
    • r=x2+y2r = \sqrt{x^2 + y^2}
    • θ=tan1(yx)\theta = \tan^{-1}\left(\frac{y}{x}\right)

Calculating:

  • For rr:
    r=32+(33)2=9+27=36=6r = \sqrt{3^2 + (3\sqrt{3})^2} = \sqrt{9 + 27} = \sqrt{36} = 6

  • For θ\theta:
    θ=tan1(333)=tan1(3)=π3\theta = \tan^{-1}\left(\frac{3\sqrt{3}}{3}\right) = \tan^{-1}(\sqrt{3}) = \frac{\pi}{3}

Thus, the Cartesian point (3,33)(3, 3\sqrt{3}) can be written as (6,π3)(6, \frac{\pi}{3}) in polar coordinates.

This comparison shows how the two systems are connected. This can help make calculations or visualizations easier depending on what we need.

Related articles

Similar Categories
Derivatives and Applications for University Calculus IIntegrals and Applications for University Calculus IAdvanced Integration Techniques for University Calculus IISeries and Sequences for University Calculus IIParametric Equations and Polar Coordinates for University Calculus II
Click HERE to see similar posts for other categories

Can You Illustrate the Relationship Between Polar and Cartesian Coordinates with Examples?

Polar coordinates and Cartesian coordinates are two different ways to show points on a flat surface. Each method has its own benefits.

Polar Coordinates:

  • They are written as (r,θ)(r, \theta), where:
    • rr is how far the point is from the center (the origin).
    • θ\theta is the angle measured from the right side (the positive x-axis).

Example:

Let’s change the polar point (5,π3)(5, \frac{\pi}{3}) into Cartesian coordinates:

  • We can use these formulas:
    • x=rcos(θ)x = r \cos(\theta)
    • y=rsin(θ)y = r \sin(\theta)

Calculating:

  • For xx:
    x=5cos(π3)=512=2.5x = 5 \cos\left(\frac{\pi}{3}\right) = 5 \cdot \frac{1}{2} = 2.5

  • For yy:
    y=5sin(π3)=5324.33y = 5 \sin\left(\frac{\pi}{3}\right) = 5 \cdot \frac{\sqrt{3}}{2} \approx 4.33

So, the polar point (5,π3)(5, \frac{\pi}{3}) is about (2.5,4.33)(2.5, 4.33) in Cartesian coordinates.

Cartesian Coordinates:

  • They are shown as (x,y)(x, y), where:
    • xx tells us how far to go left or right.
    • yy tells us how far to go up or down.

Example:

Let’s convert the Cartesian point (3,33)(3, 3\sqrt{3}) into polar coordinates:

  • We can use these formulas:
    • r=x2+y2r = \sqrt{x^2 + y^2}
    • θ=tan1(yx)\theta = \tan^{-1}\left(\frac{y}{x}\right)

Calculating:

  • For rr:
    r=32+(33)2=9+27=36=6r = \sqrt{3^2 + (3\sqrt{3})^2} = \sqrt{9 + 27} = \sqrt{36} = 6

  • For θ\theta:
    θ=tan1(333)=tan1(3)=π3\theta = \tan^{-1}\left(\frac{3\sqrt{3}}{3}\right) = \tan^{-1}(\sqrt{3}) = \frac{\pi}{3}

Thus, the Cartesian point (3,33)(3, 3\sqrt{3}) can be written as (6,π3)(6, \frac{\pi}{3}) in polar coordinates.

This comparison shows how the two systems are connected. This can help make calculations or visualizations easier depending on what we need.

Related articles