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How Can We Calculate the Maximum Height and Range of a Projectile?

To find out how high something can go and how far it can travel when launched into the air, we can use some simple formulas.

  1. Maximum Height (HH):

    You can calculate this using this formula:

    H=v02sin2θ2gH = \frac{v_0^2 \sin^2 \theta}{2g}

    Here’s what the letters mean:

    • v0v_0 is how fast the object is thrown (initial velocity).
    • θ\theta is the angle it’s thrown from (launch angle).
    • gg is the force of gravity, which is about 9.81m/s29.81 \, \text{m/s}^2.
  2. Range (RR):

    To find out how far it travels, use this formula:

    R=v02sin(2θ)gR = \frac{v_0^2 \sin(2\theta)}{g}

Here’s an example:

If you throw something at a 3030^\circ angle with a speed of 20m/s20 \, \text{m/s}, just plug those numbers into the formulas to find out the maximum height (HH) and the range (RR).

Happy calculating!

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How Can We Calculate the Maximum Height and Range of a Projectile?

To find out how high something can go and how far it can travel when launched into the air, we can use some simple formulas.

  1. Maximum Height (HH):

    You can calculate this using this formula:

    H=v02sin2θ2gH = \frac{v_0^2 \sin^2 \theta}{2g}

    Here’s what the letters mean:

    • v0v_0 is how fast the object is thrown (initial velocity).
    • θ\theta is the angle it’s thrown from (launch angle).
    • gg is the force of gravity, which is about 9.81m/s29.81 \, \text{m/s}^2.
  2. Range (RR):

    To find out how far it travels, use this formula:

    R=v02sin(2θ)gR = \frac{v_0^2 \sin(2\theta)}{g}

Here’s an example:

If you throw something at a 3030^\circ angle with a speed of 20m/s20 \, \text{m/s}, just plug those numbers into the formulas to find out the maximum height (HH) and the range (RR).

Happy calculating!

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