External conditions are very important in figuring out the work done in physics. Work can be understood using this formula:

$$W = F \cdot d \cdot \cos(\theta)$$

Here’s what the letters mean:

• W = work
• F = force applied
• d = distance moved
• θ = angle between the force and the direction of motion.

Factors That Affect Work Done:

1. Size of Force (F): If you apply a stronger force, you do more work. For example, if you push with a force of 10 N over a distance of 5 m, the work done is:

   $$W = 10\, \text{N} \cdot 5\, \text{m} = 50\, \text{J}$$

2. Distance Moved (d): The work increases when you move further. If you use that same force of 10 N but over a distance of 10 m, then the work done is:

   $$W = 10\, \text{N} \cdot 10\, \text{m} = 100\, \text{J}$$

3. Angle (θ): The angle at which you apply the force also changes how much work you do. If you push in the same direction as the motion (( \theta = 0^\circ )), you get the most work done since ( \cos(0) = 1 ). But if you push at a right angle (( \theta = 90^\circ )), no work is done because ( \cos(90^\circ) = 0 ).

External Conditions:

• Friction and Air Resistance: These can reduce the total work you can do. High friction can make your force less effective.

• Incline: When you are working against gravity, like going up a hill, you need to apply more force to move something up than if you were pushing it on level ground.

In summary, factors like force, distance, angle, and things that slow you down can greatly affect the amount of work done in physical tasks.