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How Do You Identify the Center and Radius of a Circle from Its Equation?

When you want to find the center and radius of a circle from its equation, it's actually pretty simple once you understand it!

Most circles can be shown with a standard equation. It looks like this:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

In this equation, (h,k)(h, k) is the center of the circle, and rr is the radius. Let’s go through the steps on how to find these important parts.

Step 1: Check the Equation Format

First, make sure the circle's equation follows the standard format.

If you see something different, like x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0, don't worry! You can change it to find the center and radius.

Step 2: Rearrange the Equation

For example, if your equation is x2+y26x+8y9=0x^2 + y^2 - 6x + 8y - 9 = 0, you need to reorganize it into that nice standard form. Here’s how you can do it:

  1. Move the constant (the number without x or y) to the other side: x2+y26x+8y=9x^2 + y^2 - 6x + 8y = 9

  2. Group the x’s and y’s together: (x26x)+(y2+8y)=9(x^2 - 6x) + (y^2 + 8y) = 9

Step 3: Complete the Square

Next, you will complete the square for both the x and y parts. This sounds tricky, but it’s easier than it seems!

  1. For x26xx^2 - 6x, take half of -6 (which is -3), square it (you get 9), and add this to both sides: (x26x+9)+(y2+8y)=9+9(x^2 - 6x + 9) + (y^2 + 8y) = 9 + 9 Now you have: (x3)2+(y2+8y)=18(x - 3)^2 + (y^2 + 8y) = 18

  2. Next, for y2+8yy^2 + 8y, take half of 8 (which is 4), square it (you get 16), and add this to both sides: (x3)2+(y2+8y+16)=18+16(x - 3)^2 + (y^2 + 8y + 16) = 18 + 16 Now it looks like this: (x3)2+(y+4)2=34(x - 3)^2 + (y + 4)^2 = 34

Step 4: Find the Center and Radius

Now that we have the equation in standard form (x3)2+(y+4)2=34(x - 3)^2 + (y + 4)^2 = 34, we can easily find the center and radius.

  • Center: Here, (h,k)=(3,4)(h, k) = (3, -4). Remember, the signs flip because of how the equation is set up with (xh)(x - h) and (yk)(y - k). So the center is (3,4)(3, -4).

  • Radius: To find the radius, just take the square root of the number on the right side. Since r2=34r^2 = 34, the radius is r=34r = \sqrt{34}.

Recap

  1. If needed, rearrange the equation into standard form.
  2. Complete the square for both x and y parts.
  3. Find the center as (h,k)(h, k) and use the formula r=r2r = \sqrt{r^2} to get the radius.

With some practice, this process will become easy! It’s like a fun math skill that feels great when you get it all figured out. Plus, it will help a lot when you draw circles or work on more complicated geometry later on. Just remember to go slowly and follow each step!

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How Do You Identify the Center and Radius of a Circle from Its Equation?

When you want to find the center and radius of a circle from its equation, it's actually pretty simple once you understand it!

Most circles can be shown with a standard equation. It looks like this:

(xh)2+(yk)2=r2(x - h)^2 + (y - k)^2 = r^2

In this equation, (h,k)(h, k) is the center of the circle, and rr is the radius. Let’s go through the steps on how to find these important parts.

Step 1: Check the Equation Format

First, make sure the circle's equation follows the standard format.

If you see something different, like x2+y2+Dx+Ey+F=0x^2 + y^2 + Dx + Ey + F = 0, don't worry! You can change it to find the center and radius.

Step 2: Rearrange the Equation

For example, if your equation is x2+y26x+8y9=0x^2 + y^2 - 6x + 8y - 9 = 0, you need to reorganize it into that nice standard form. Here’s how you can do it:

  1. Move the constant (the number without x or y) to the other side: x2+y26x+8y=9x^2 + y^2 - 6x + 8y = 9

  2. Group the x’s and y’s together: (x26x)+(y2+8y)=9(x^2 - 6x) + (y^2 + 8y) = 9

Step 3: Complete the Square

Next, you will complete the square for both the x and y parts. This sounds tricky, but it’s easier than it seems!

  1. For x26xx^2 - 6x, take half of -6 (which is -3), square it (you get 9), and add this to both sides: (x26x+9)+(y2+8y)=9+9(x^2 - 6x + 9) + (y^2 + 8y) = 9 + 9 Now you have: (x3)2+(y2+8y)=18(x - 3)^2 + (y^2 + 8y) = 18

  2. Next, for y2+8yy^2 + 8y, take half of 8 (which is 4), square it (you get 16), and add this to both sides: (x3)2+(y2+8y+16)=18+16(x - 3)^2 + (y^2 + 8y + 16) = 18 + 16 Now it looks like this: (x3)2+(y+4)2=34(x - 3)^2 + (y + 4)^2 = 34

Step 4: Find the Center and Radius

Now that we have the equation in standard form (x3)2+(y+4)2=34(x - 3)^2 + (y + 4)^2 = 34, we can easily find the center and radius.

  • Center: Here, (h,k)=(3,4)(h, k) = (3, -4). Remember, the signs flip because of how the equation is set up with (xh)(x - h) and (yk)(y - k). So the center is (3,4)(3, -4).

  • Radius: To find the radius, just take the square root of the number on the right side. Since r2=34r^2 = 34, the radius is r=34r = \sqrt{34}.

Recap

  1. If needed, rearrange the equation into standard form.
  2. Complete the square for both x and y parts.
  3. Find the center as (h,k)(h, k) and use the formula r=r2r = \sqrt{r^2} to get the radius.

With some practice, this process will become easy! It’s like a fun math skill that feels great when you get it all figured out. Plus, it will help a lot when you draw circles or work on more complicated geometry later on. Just remember to go slowly and follow each step!

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