To find the intercepts of a quadratic equation, you can follow these simple steps:

1. Finding the Y-Intercept:

   • First, set $x = 0$.
   • Now, solve for $y$.
   • If your equation looks like this: $y = ax^2 + bx + c$, you will get the point $(0, c)$.

2. Finding the X-Intercepts:

   • Here, you set $y = 0$ and work with the equation $ax^2 + bx + c = 0$.
   • You can use the quadratic formula to help you. It looks like this:

   $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

This formula will show you the values of $x$ where the graph crosses the x-axis!

So, just remember, for the Y-intercept, you put $x$ to 0, and for the X-intercepts, you set $y$ to 0 and use the quadratic formula. Happy solving!